丝路新程的安防系统逻辑门判断。以下程序的输出结果是？

int a = 1, b = 0, c = 1;
if ((a && b) || (b && c) || (a && c)) {
if (!(a || b || c)) cout << "Safe";
else cout << "Warning";
} else {
cout << "Normal";
}