不管输入的n和k具体为多少,t=2时的猜测数总是小于等于t=1时的猜测数。
#include <algorithm>
#include <cstdio>
#include <cstring>
#define ll long long
int cnt_broken = 0;
int cnt_check = 0;
int n, k;
inline bool check(int h) {
printf("now check:%d\n", h);
++cnt_check;
if (cnt_broken == 2) {
printf("You have no egg!\n");
return false;
}
if (h >= k) {
++cnt_broken;
return true;
} else {
return false;
}
}
inline bool assert_ans(int h) {
if (h == k) {
printf("You are Right using %d checks\n", cnt_check);
return true;
} else {
printf("Wrong answer!\n");
return false;
}
}
inline void guess1(int n) {
for (int i = 1; i <= n; ++i)
if (check(i)) {
assert_ans(i);
return;
}
}
inline void guess2(int n) {
int w = 0;
for (int ti = w, nh = w;; --ti, nh += ti, nh = std::min(nh, n)) {
if (check(nh)) {
for (int j = nh - ti + 1; j < nh; ++j)
if (check(j))
assert_ans(j);
return;
}
assert_ans(nh);
return;
}
}
int main() {
scanf("%d%d", &n, &k);
int t;
scanf("%d",&t);
if(t==1){
guess1(n);
}else{
guess2(n);
}
return 0;
}
正确
错误